a-conjugated-alkene-has-an-energy-gap-of-250-kjmol-calculate-the-lambda-max-usin

Question

A conjugated alkene has an energy gap of 250 kJ/mol. Calculate the lambda max using the formula E = hc/λ. (h = 6.626 x 10^-34 Js, c = $$3.00 x 10^8 m/s)$$

Accepted Answer

479 nm

Answer

750 nm

Answer

300 nm

Answer

250 nm

A conjugated alkene has an energy gap of 250 kJ/mol. Calculate the lambda max using the formula E = hc/λ. (h = 6.626 x 10^-34 Js, c = 3.00 x 10^8 m/s)