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Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds
Wade - Organic Chemistry 9th Edition
Wade9th EditionOrganic ChemistryISBN: 9780135213728Not the one you use?Change textbook
Chapter 22, Problem 28b

Predict the major products of the following base-catalyzed aldol condensations with dehydration.
(b) 2,2-dimethylpropanal + acetophenone

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1
Step 1: Identify the reactants and their functional groups. In this case, 2,2-dimethylpropanal is an aldehyde, and acetophenone is a ketone. Both contain carbonyl groups (C=O), which are key to the aldol condensation reaction.
Step 2: Determine the enolate formation. Under basic conditions, the alpha-hydrogen (hydrogen attached to the carbon adjacent to the carbonyl group) of acetophenone is abstracted by the base, forming an enolate ion. The enolate ion is nucleophilic and will attack the electrophilic carbonyl carbon of 2,2-dimethylpropanal.
Step 3: Perform the nucleophilic addition step. The enolate ion from acetophenone attacks the carbonyl carbon of 2,2-dimethylpropanal, forming a beta-hydroxy ketone intermediate. This intermediate is the product of the aldol addition step.
Step 4: Dehydration of the beta-hydroxy ketone. Under base-catalyzed conditions, the beta-hydroxy ketone undergoes elimination of water (dehydration) to form an α,β-unsaturated ketone. This step involves the formation of a double bond between the alpha and beta carbons.
Step 5: Predict the major product. The major product will be the α,β-unsaturated ketone formed after dehydration. The structure will include the acetophenone-derived aromatic ring and the double bond introduced during the dehydration step.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Aldol Condensation

Aldol condensation is a reaction between aldehydes or ketones that contain alpha-hydrogens, leading to the formation of β-hydroxy aldehydes or ketones. In the presence of a base, one carbonyl compound is deprotonated to form an enolate ion, which then attacks the carbonyl carbon of another molecule, resulting in a β-hydroxy carbonyl compound. This intermediate can further undergo dehydration to yield an α,β-unsaturated carbonyl compound.
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Base Catalysis

Base catalysis involves the use of a base to facilitate a chemical reaction, often by deprotonating a molecule to generate a reactive intermediate. In aldol condensations, a strong base like sodium hydroxide or potassium hydroxide is used to deprotonate the alpha-hydrogen of the aldehyde or ketone, forming an enolate ion that can attack another carbonyl compound. This step is crucial for the formation of the aldol product.
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Dehydration Reaction

Dehydration is the process of removing a water molecule from a compound, often occurring in organic reactions to form double bonds. In the context of aldol condensation, after the formation of the β-hydroxy carbonyl compound, dehydration occurs, leading to the formation of an α,β-unsaturated carbonyl compound. This step is essential for completing the aldol condensation and is driven by the stability of the resulting conjugated system.
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