Textbook Question
Circle the coplanar atoms in the following structure:
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Ch.1 - Structure and Bonding
Wade9th EditionOrganic ChemistryISBN: 9780135213728
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Table of contents
- Ch.1 - Structure and Bonding107
- Ch. 2 - Acids and Bases; Functional Groups115
- Ch.3 - Structure and Stereochemistry of Alkanes100
- Ch.4 - The Study of Chemical Reactions99
- Ch.5 - Stereochemistry93
- Ch.6 - Alkyl Halides; Nucleophilic Substitution118
- Ch. 7 - Structure and Synthesis of Alkenes; Elimination158
- Ch.8 - Reactions of Alkenes171
- Ch.9 - Alkynes91
- Ch.10 - Structure and Synthesis of Alcohols143
- Ch.11 - Reactions of Alcohols104
- Ch. 12 - Infrared Spectroscopy and Mass Spectrometry22
- Ch. 13 - Nuclear Magnetic Resonance Spectroscopy45
- Ch. 14 - Ethers, Epoxides, and Thioethers72
- Ch. 15 - Conjugated Systems, Orbital Symmetry, and Ultraviolet Spectroscopy89
- Ch. 16 - Aromatic Compounds74
- Ch. 17 - Reactions of Aromatic Compounds126
- Ch. 18 - Ketones and Aldehydes193
- Ch. 19 - Amines129
- Ch. 20 - Carboxylic Acids77
- Ch. 21 - Carboxylic Acid Derivatives141
- Ch. 22 - Condensations and Alpha Substitutions of Carbonyl Compounds175
- Ch. 23 - Carbohydrates and Nucleic Acids93
- Ch. 24 - Amino Acids, Peptides, and Proteins54
Chapter 1, Problem 58d,e,f
Which of the following compounds show cis-trans isomerism? Draw the cis and trans isomers of the ones that do.
(d) 
(e) 
(f) CH3CH=NCH3
Verified step by step guidance1
Step 1: Understand the concept of cis-trans isomerism. Cis-trans isomerism occurs in compounds with restricted rotation around a double bond or a ring structure, where two substituents can be positioned on the same side (cis) or opposite sides (trans).
Step 2: Analyze compound (d), cyclopentene. Cyclopentene has a double bond within a ring structure. Since the ring restricts rotation, cis-trans isomerism is possible. Draw the cis isomer with both substituents on the same side of the double bond and the trans isomer with substituents on opposite sides.
Step 3: Analyze compound (e), CH3CH=C(CH2CH2CH3)CH2CH3. This compound has a double bond between CH3CH and C(CH2CH2CH3). Check if the two groups attached to the double-bonded carbons are different. Since they are different, cis-trans isomerism is possible. Draw the cis isomer with the larger groups (CH2CH2CH3 and CH2CH3) on the same side and the trans isomer with them on opposite sides.
Step 4: Analyze compound (f), CH3CH=NCH3. This compound has a double bond between CH3CH and NCH3. However, nitrogen in the double bond does not allow for cis-trans isomerism because it does not have two distinct substituents attached to it. Therefore, cis-trans isomerism is not possible for this compound.
Step 5: Summarize the findings. Cis-trans isomerism is possible for compounds (d) cyclopentene and (e) CH3CH=C(CH2CH2CH3)CH2CH3. Draw the cis and trans isomers for these compounds as described in steps 2 and 3. Compound (f) does not exhibit cis-trans isomerism.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Cis-Trans Isomerism
Cis-trans isomerism, also known as geometric isomerism, occurs in compounds with restricted rotation around a double bond or a ring structure. In cis isomers, substituents are on the same side of the double bond or ring, while in trans isomers, they are on opposite sides. This difference in spatial arrangement can lead to distinct physical and chemical properties.
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Is the following cyclohexane cis or trans?
Alkenes and Ring Structures
Alkenes are hydrocarbons that contain at least one carbon-carbon double bond, which is crucial for the existence of cis-trans isomers. Additionally, cyclic compounds, like cyclopentene, can also exhibit this type of isomerism due to the rigidity of their structure, which restricts the rotation around the double bond, allowing for different spatial arrangements of substituents.
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Drawing Isomers
To illustrate cis and trans isomers, one must accurately represent the molecular structure, showing the relative positions of substituents around the double bond or ring. This involves using structural formulas to depict the connectivity of atoms and ensuring that the orientation of groups reflects whether they are on the same side (cis) or opposite sides (trans) of the double bond or ring.
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01:10What is a constitutional isomer?
Related Practice
Textbook Question
Dimethyl sulfoxide (DMSO) has been used as an anti-inflammatory rub for race horses. DMSO and acetone appear to have similar structures, but the C=O carbon atom in acetone is planar, while the S=O sulfur atom in DMSO is pyramidal. Draw Lewis structures for DMSO and acetone, predict the hybridizations, and explain these observations.
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Textbook Question
Give the relationships between the following pairs of structures. The possible relationships are as follows: same compound, cis-trans isomers, constitutional (structural) isomers, and not isomers (different molecular formula).
(c)
(d)
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Textbook Question
Give the relationships between the following pairs of structures. The possible relationships are as follows: same compound, cis-trans isomers, constitutional (structural) isomers, and not isomers (different molecular formula).
(a) CH3CH2CH2CH3 and (CH3)3CH
(b) CH2=CH–CH2Cl and CHCl=CH–CH3
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Textbook Question
Which of the following compounds show cis-trans isomerism? Draw the cis and trans isomers of the ones that do.
(a) CH3CH=CHCH3
(b) CH3C≡CCH3
(c) CH2=C(CH3)2
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Textbook Question
In pent-2-yne (CH3CCCH2CH3), there are four atoms in a straight line. Use dashed lines and wedges to draw a three-dimensional representation of this molecule, and circle the four atoms that are in a straight line.
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