Skip to main content
Ch. 2 - Graphs and Functions
Lial - College Algebra 13th Edition
Lial13th EditionCollege AlgebraISBN: 9780136881063Not the one you use?Change textbook
Chapter 3, Problem 41

Describe the graph of each equation as a circle, a point, or nonexistent. If it is a circle, give the center and radius. If it is a point, give the coordinates. x2+y2+4x+14y=-54

Verified step by step guidance
1
Start by rewriting the given equation: \(x^2 + y^2 + 4x + 14y = -54\).
Group the \(x\) terms and \(y\) terms together: \((x^2 + 4x) + (y^2 + 14y) = -54\).
Complete the square for the \(x\) terms: take half of 4, which is 2, and square it to get 4. Add and subtract 4 inside the equation.
Complete the square for the \(y\) terms: take half of 14, which is 7, and square it to get 49. Add and subtract 49 inside the equation.
Rewrite the equation as perfect square trinomials: \((x + 2)^2 - 4 + (y + 7)^2 - 49 = -54\). Then, combine constants on the right side to find the standard form of the circle equation.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
3m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Standard Form of a Circle Equation

The standard form of a circle's equation is (x - h)^2 + (y - k)^2 = r^2, where (h, k) is the center and r is the radius. Converting a general quadratic equation into this form helps identify the circle's properties.
Recommended video:
5:18
Circles in Standard Form

Completing the Square

Completing the square is a method used to rewrite quadratic expressions as perfect square trinomials. This technique is essential to transform the given equation into the standard form of a circle.
Recommended video:
06:24
Solving Quadratic Equations by Completing the Square

Interpreting the Radius and Existence of the Circle

After rewriting the equation, the radius squared (r^2) must be positive for a circle to exist. If r^2 = 0, the graph is a single point; if r^2 is negative, the graph does not exist in the real plane.
Recommended video:
5:18
Circles in Standard Form