Use the method described in Exercises 83–86, if applicable, and properties of absolute value to solve each equation or inequality. (Hint: Exercises 99 and 100 can be solved by inspection.) | 4x2 - 23x - 6 | = 0
Ch. 1 - Equations and Inequalities

Chapter 2, Problem 95
Solve each equation. 4(x+1)4-13(x+1)2=-9
Verified step by step guidance1
Start by making a substitution to simplify the equation. Let \(y = (x+1)^2\). This transforms the original equation \(4(x+1)^4 - 13(x+1)^2 = -9\) into \(4y^2 - 13y = -9\).
Rewrite the equation in standard quadratic form by moving all terms to one side: \(4y^2 - 13y + 9 = 0\).
Solve the quadratic equation \(4y^2 - 13y + 9 = 0\) using the quadratic formula: \(y = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\), where \(a=4\), \(b=-13\), and \(c=9\).
After finding the values of \(y\), recall that \(y = (x+1)^2\). For each solution \(y_i\), solve the equation \((x+1)^2 = y_i\) by taking the square root of both sides: \(x+1 = \pm \sqrt{y_i}\).
Finally, solve for \(x\) by isolating it: \(x = -1 \pm \sqrt{y_i}\). These values of \(x\) are the solutions to the original equation.

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7mKey Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Substitution Method
The substitution method involves replacing a complex expression with a single variable to simplify the equation. In this problem, letting y = (x + 1)^2 transforms the quartic equation into a quadratic form, making it easier to solve.
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Solving Quadratic Equations
Once the equation is rewritten as a quadratic in terms of y, techniques such as factoring, completing the square, or using the quadratic formula can be applied to find the values of y. These solutions are then used to find x.
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Back-Substitution and Solving for x
After finding the values of y, substitute back y = (x + 1)^2 to solve for x. This typically involves taking square roots and considering both positive and negative roots to find all possible solutions.
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