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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 8, Problem 8.8.24

The integrals in Exercises 1–34 converge. Evaluate the integrals without using tables.
∫₋∞^∞ 2x e^(−x²) dx

Verified step by step guidance
1
Recognize that the integral is an improper integral over the entire real line, from \(-\infty\) to \(\infty\), of the function \(2x e^{-x^{2}}\).
Note that the integrand \(2x e^{-x^{2}}\) is an odd function because \(2(-x) e^{-(-x)^{2}} = -2x e^{-x^{2}}\), which is the negative of the original function.
Recall that the integral of any odd function over symmetric limits \([-a, a]\) is zero, provided the integral converges.
Since the limits are \(-\infty\) to \(\infty\), which are symmetric about zero, and the function is odd and integrable, the integral evaluates to zero.
Therefore, without performing any integration by parts or substitution, conclude that the value of the integral is zero due to the symmetry of the integrand.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Improper Integrals

Improper integrals involve integration over infinite limits or integrands with infinite discontinuities. To evaluate them, one typically takes limits of definite integrals as the bounds approach infinity. Understanding convergence is crucial to ensure the integral has a finite value.
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Properties of Even and Odd Functions

Even functions satisfy f(−x) = f(x), and odd functions satisfy f(−x) = −f(x). When integrating over symmetric limits (−a to a), the integral of an odd function is zero, while the integral of an even function is twice the integral from 0 to a. Recognizing function symmetry simplifies evaluation.
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Integration of Exponential Functions with Quadratic Exponents

Integrals involving e^(−x²) are common in calculus and probability. While the integral of e^(−x²) has no elementary antiderivative, multiplying by x or other polynomials can allow evaluation using substitution or recognizing derivative forms. This helps in solving integrals like ∫ x e^(−x²) dx.
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