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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 8, Problem 8.8.34

The integrals in Exercises 1–34 converge. Evaluate the integrals without using tables.
∫₀^∞ dx / [(x + 1)(x² + 1)]

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1
Start by expressing the integrand \( \frac{1}{(x+1)(x^2+1)} \) as a sum of partial fractions. Set up the equation: \[ \frac{1}{(x+1)(x^2+1)} = \frac{A}{x+1} + \frac{Bx + C}{x^2 + 1} \] where \(A\), \(B\), and \(C\) are constants to be determined.
Multiply both sides of the equation by \( (x+1)(x^2+1) \) to clear the denominators, resulting in: \[ 1 = A(x^2 + 1) + (Bx + C)(x + 1) \]. Expand the right-hand side and collect like terms in powers of \(x\).
Equate the coefficients of corresponding powers of \(x\) on both sides to form a system of equations for \(A\), \(B\), and \(C\). Solve this system to find the values of these constants.
Rewrite the integral as the sum of integrals of the partial fractions: \[ \int_0^\infty \frac{dx}{(x+1)(x^2+1)} = \int_0^\infty \frac{A}{x+1} dx + \int_0^\infty \frac{Bx + C}{x^2 + 1} dx \].
Evaluate each integral separately. For \( \int \frac{1}{x+1} dx \), use the natural logarithm function. For \( \int \frac{x}{x^2 + 1} dx \), use substitution \( u = x^2 + 1 \). For \( \int \frac{1}{x^2 + 1} dx \), use the arctangent function. Then, apply the limits from 0 to \( \infty \) carefully to find the value of the original integral.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Improper Integrals

Improper integrals involve integration over an infinite interval or integrands with infinite discontinuities. To evaluate them, we take limits of definite integrals as the bounds approach infinity or the points of discontinuity. This ensures the integral converges to a finite value.
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