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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 8, Problem 8.2.2

Evaluate the integrals in Exercises 1–24 using integration by parts.
∫ θ cos(πθ) dθ

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1
Identify the parts of the integral for integration by parts. Let \(u = \theta\) and \(dv = \cos(\pi \theta) \, d\theta\).
Compute the derivatives and antiderivatives needed: \(du = d\theta\) and \(v = \int \cos(\pi \theta) \, d\theta\). To find \(v\), recall that \(\int \cos(ax) \, dx = \frac{1}{a} \sin(ax) + C\), so here \(v = \frac{1}{\pi} \sin(\pi \theta)\).
Apply the integration by parts formula: \(\int u \, dv = uv - \int v \, du\). Substitute the expressions found: \(\int \theta \cos(\pi \theta) \, d\theta = \theta \cdot \frac{1}{\pi} \sin(\pi \theta) - \int \frac{1}{\pi} \sin(\pi \theta) \, d\theta\).
Simplify the integral: \(\int \frac{1}{\pi} \sin(\pi \theta) \, d\theta = \frac{1}{\pi} \int \sin(\pi \theta) \, d\theta\). Use the integral formula \(\int \sin(ax) \, dx = -\frac{1}{a} \cos(ax) + C\) to evaluate this integral.
Combine all parts to write the expression for the original integral, including the constant of integration \(C\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Integration by Parts

Integration by parts is a technique derived from the product rule of differentiation. It transforms the integral of a product of functions into simpler integrals using the formula ∫u dv = uv - ∫v du. Choosing u and dv wisely simplifies the problem.
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Integration by Parts for Definite Integrals

Choosing u and dv

Selecting which part of the integrand to assign as u and which as dv is crucial. Typically, u is chosen as a function that simplifies when differentiated, and dv as a function that is easy to integrate. This choice affects the ease of solving the integral.
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Choosing a Convergence Test

Integrating Trigonometric Functions

Integrating functions like cos(πθ) involves recognizing standard integral forms. The integral of cos(kθ) with respect to θ is (1/k)sin(kθ) + C, where k is a constant. This knowledge helps in computing the integral of dv in integration by parts.
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Introduction to Trigonometric Functions