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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 8, Problem 8.4.4

Evaluate the integrals in Exercises 1–14.
∫ dx / (8 + 2x²) from 0 to 2

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1
Identify the integral to be evaluated: \(\displaystyle \int_0^2 \frac{dx}{8 + 2x^2}\).
Factor out constants from the denominator to simplify the integral: rewrite the denominator as \(2(4 + x^2)\), so the integral becomes \(\displaystyle \int_0^2 \frac{dx}{2(4 + x^2)} = \frac{1}{2} \int_0^2 \frac{dx}{4 + x^2}\).
Recognize the integral form \(\int \frac{dx}{a^2 + x^2}\), which has the antiderivative \(\frac{1}{a} \arctan\left(\frac{x}{a}\right) + C\). Here, \(a^2 = 4\), so \(a = 2\).
Apply the antiderivative formula to the integral: \(\frac{1}{2} \int_0^2 \frac{dx}{4 + x^2} = \frac{1}{2} \left[ \frac{1}{2} \arctan\left( \frac{x}{2} \right) \right]_0^2\).
Evaluate the definite integral by substituting the limits \(x=2\) and \(x=0\) into the antiderivative expression and subtracting: \(\frac{1}{4} \left( \arctan(1) - \arctan(0) \right)\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Definite Integrals

A definite integral calculates the net area under a curve between two specified limits. It is represented as ∫ from a to b of f(x) dx, where a and b are the lower and upper bounds. Evaluating a definite integral involves finding the antiderivative and then applying the Fundamental Theorem of Calculus.
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Integration of Rational Functions

Integrating rational functions often requires recognizing standard integral forms or using substitution. For integrals involving expressions like 1/(a + bx²), the result typically involves inverse trigonometric functions such as arctangent, especially when the denominator is a sum of squares.
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Substitution Method

The substitution method simplifies integrals by changing variables to transform the integral into a more familiar form. For example, substituting u = x√(coefficient) can help rewrite the integral into a standard arctangent form, making it easier to evaluate.
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