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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 7, Problem 7.3.85

In Exercises 59–86, find the derivative of y with respect to the given independent variable.
85. y = log₂(8t^(ln 2))

Verified step by step guidance
1
Recall the change of base formula for logarithms: \(\log_a b = \frac{\ln b}{\ln a}\). Use this to rewrite \(y = \log_2 \left(8t^{\ln 2}\right)\) as \(y = \frac{\ln \left(8t^{\ln 2}\right)}{\ln 2}\).
Apply the logarithm property \(\ln(ab) = \ln a + \ln b\) to expand the numerator: \(\ln \left(8t^{\ln 2}\right) = \ln 8 + \ln \left(t^{\ln 2}\right)\).
Use the power rule for logarithms: \(\ln \left(t^{\ln 2}\right) = (\ln 2) \cdot \ln t\). So the expression becomes \(y = \frac{\ln 8 + (\ln 2) \cdot \ln t}{\ln 2}\).
Since \(\ln 8\) and \(\ln 2\) are constants, separate the terms: \(y = \frac{\ln 8}{\ln 2} + \frac{(\ln 2) \cdot \ln t}{\ln 2}\). Simplify the second term by canceling \(\ln 2\).
Now differentiate \(y\) with respect to \(t\). The first term is constant, so its derivative is zero. For the second term, differentiate \(\ln t\) using \(\frac{d}{dt} \ln t = \frac{1}{t}\). Combine these results to find \(\frac{dy}{dt}\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Logarithmic Functions and Their Properties

Logarithmic functions are the inverses of exponential functions. Key properties include the change of base formula and the laws of logarithms, such as log_b(xy) = log_b(x) + log_b(y). Understanding these properties helps simplify expressions before differentiation.
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Chain Rule

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The derivative of log base b of x is 1/(x ln b). This formula generalizes the natural logarithm derivative and is essential when differentiating logarithms with bases other than e.
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