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Ch. 7 - Transcendental Functions
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 7, Problem 7.5.1

In Exercises 1–6, use l’Hôpital’s Rule to evaluate the limit. Then evaluate the limit using a method studied in Chapter 2.
1. lim (x → -2) (x + 2) / (x² - 4)

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First, identify the form of the limit by substituting \(x = -2\) into the expression \(\frac{x + 2}{x^{2} - 4}\). Check if it results in an indeterminate form like \(\frac{0}{0}\) or \(\frac{\infty}{\infty}\), which allows the use of l'Hôpital's Rule.
Since direct substitution gives \(\frac{0}{0}\), apply l'Hôpital's Rule by differentiating the numerator and denominator separately with respect to \(x\). The derivative of the numerator \(x + 2\) is \(1\), and the derivative of the denominator \(x^{2} - 4\) is \$2x$.
Rewrite the limit using these derivatives: \(\lim_{x \to -2} \frac{1}{2x}\). Now, substitute \(x = -2\) into this new expression to find the limit.
To verify the result using a method from Chapter 2, factor the denominator \(x^{2} - 4\) as \((x - 2)(x + 2)\). Then simplify the original expression \(\frac{x + 2}{(x - 2)(x + 2)}\) by canceling the common factor \((x + 2)\), keeping in mind the domain restrictions.
After simplification, evaluate the limit of the simplified expression as \(x\) approaches \(-2\) by direct substitution, confirming the result obtained using l'Hôpital's Rule.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Limits and Indeterminate Forms

Limits describe the behavior of a function as the input approaches a particular value. When direct substitution results in an indeterminate form like 0/0, special techniques such as l’Hôpital’s Rule are needed to evaluate the limit.
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l’Hôpital’s Rule

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