Textbook Question
In Exercises 1–24, find the derivative of y with respect to the appropriate variable.
19. y = t arctan(t) - 1/2 ln(t)
Ch. 7 - Transcendental Functions
Hass15th EditionThomas' CalculusISBN: 9780137616077
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Table of contents
- Ch. 1 - Functions155
- Ch. 2 - Limits and Continuity240
- Ch. 3 - Derivatives337
- Ch. 4 - Applications of Derivatives293
- Ch. 5 - Integrals41
- Ch. 6 - Applications of Definite Integrals25
- Ch. 7 - Transcendental Functions490
- Ch. 8 - Techniques of Integration399
- Ch. 9 - First-Order Differential Equations66
- Ch. 10 - Infinite Sequences and Series132
- Ch. 11 - Parametric Equations and Polar Coordinates58
Chapter 7, Problem 7.PE.129
In Exercises 129–132 solve the initial value problem.
129. dy/dx = e^(-x-y-2), y(0) = -2
Verified step by step guidance1
Identify the type of differential equation given: \( \frac{dy}{dx} = e^{-x - y - 2} \). Notice that the right side can be rewritten to separate variables.
Rewrite the equation by expressing the right side as \( e^{-x - y - 2} = e^{-2} \cdot e^{-x} \cdot e^{-y} \). This helps in separating variables \( x \) and \( y \).
Separate variables by rewriting the equation as \( e^{y} dy = e^{-2} e^{-x} dx \). This places all \( y \)-terms on one side and all \( x \)-terms on the other.
Integrate both sides: \( \int e^{y} dy = e^{-2} \int e^{-x} dx \). Remember to include the constant of integration after integrating.
Use the initial condition \( y(0) = -2 \) to solve for the constant of integration, then express \( y \) explicitly as a function of \( x \) if possible.
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Initial Value Problem (IVP)
An initial value problem involves solving a differential equation with a given initial condition, which specifies the value of the unknown function at a particular point. This condition allows for finding a unique solution that fits both the differential equation and the initial value.
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Separable Differential Equations
A separable differential equation can be written so that all terms involving one variable are on one side and all terms involving the other variable are on the opposite side. This allows integration of both sides separately to find the general solution.
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Integration of Exponential Functions
Integrating exponential functions often involves recognizing the form e^(ax+b) and applying substitution if necessary. Understanding how to integrate these functions is essential for solving differential equations involving exponentials.
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Related Practice
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