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Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 4, Problem 4.7.85

Initial Value Problems


Solve the initial value problems in Exercises 71–90.


d²r/dt² = 2/t³; dr/dt|ₜ ₌ ₁ =1, r(1) = 1

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Identify the given differential equation and initial conditions: \( \frac{d^{2}r}{dt^{2}} = \frac{2}{t^{3}} \), with \( \frac{dr}{dt}\bigg|_{t=1} = 1 \) and \( r(1) = 1 \).
Integrate the second derivative \( \frac{d^{2}r}{dt^{2}} \) with respect to \( t \) to find the first derivative \( \frac{dr}{dt} \). This means computing \( \int \frac{2}{t^{3}} \, dt \). Remember to add an integration constant \( C_1 \).
Use the initial condition \( \frac{dr}{dt}\big|_{t=1} = 1 \) to solve for the constant \( C_1 \) after finding the general form of \( \frac{dr}{dt} \).
Integrate the expression for \( \frac{dr}{dt} \) with respect to \( t \) to find \( r(t) \). Again, include a second integration constant \( C_2 \).
Apply the initial condition \( r(1) = 1 \) to solve for \( C_2 \), completing the solution for \( r(t) \).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Second-Order Differential Equations

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When the differential equation has terms like 2/t³, integration involves handling variable coefficients carefully, often requiring substitution or direct integration of power functions.
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