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Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 4, Problem 4.7.54

Finding Indefinite Integrals


In Exercises 17–56, find the most general antiderivative or indefinite integral. You may need to try a solution and then adjust your guess. Check your answers by differentiation.


∫(1 − cot²x) dx

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1
Recall the trigonometric identity involving cotangent and cosecant: \(\cot^{2}x + 1 = \csc^{2}x\). From this, express \(1 - \cot^{2}x\) in terms of \(\csc^{2}x\).
Rewrite the integrand using the identity: \(1 - \cot^{2}x = \csc^{2}x\).
Recognize that the integral now becomes \(\int \csc^{2}x \, dx\), which is a standard integral in calculus.
Recall the antiderivative of \(\csc^{2}x\) is \(-\cot x + C\), where \(C\) is the constant of integration.
Write the general solution as \(-\cot x + C\) and verify by differentiating \(-\cot x\) to ensure it returns the original integrand \(1 - \cot^{2}x\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Indefinite Integral and Antiderivative

An indefinite integral represents the most general antiderivative of a function, including an arbitrary constant C. It reverses differentiation, finding a function whose derivative matches the integrand. Understanding this helps in solving integrals without specified limits.
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Trigonometric Identities

Trigonometric identities, such as 1 + cot²x = csc²x, simplify integrals involving trigonometric functions. Recognizing and applying these identities transforms complex expressions into integrable forms, making the integration process more straightforward.
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Verification by Differentiation

After finding an antiderivative, differentiating it should return the original integrand. This verification step ensures the correctness of the solution and helps identify any errors in the integration process.
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