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Ch. 4 - Applications of Derivatives
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 4, Problem 4.7.35

Finding Indefinite Integrals


In Exercises 17–56, find the most general antiderivative or indefinite integral. You may need to try a solution and then adjust your guess. Check your answers by differentiation.


∫(−2cost) dt

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1
Identify the integral to solve: \(\int (-2 \cos t) \, dt\).
Recall the basic integral formula for cosine: \(\int \cos t \, dt = \sin t + C\).
Apply the constant multiple rule for integrals: \(\int k f(t) \, dt = k \int f(t) \, dt\), where \(k\) is a constant.
Rewrite the integral using the constant multiple: \(\int (-2 \cos t) \, dt = -2 \int \cos t \, dt\).
Integrate \(\cos t\) and multiply by \(-2\): \(-2 \sin t + C\), where \(C\) is the constant of integration.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Indefinite Integral

An indefinite integral represents the family of all antiderivatives of a function and is expressed with a constant of integration, C. It reverses differentiation, meaning if F'(x) = f(x), then ∫f(x) dx = F(x) + C.
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Integration of Trigonometric Functions

Integrating trigonometric functions like cosine involves knowing their antiderivatives. For example, the integral of cos(t) dt is sin(t) + C, and constants can be factored out to simplify the process.
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Verification by Differentiation

After finding an indefinite integral, differentiating the result should return the original integrand. This step confirms the correctness of the antiderivative and helps identify any errors in the integration process.
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