Textbook Question
In Exercises 41–44, determine whether the piecewise-defined function is differentiable at x = 0.
f(x) = { 2x + tan x, x ≥ 0
x², x < 0
Ch. 3 - Derivatives
Hass15th EditionThomas' CalculusISBN: 9780137616077
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Table of contents
- Ch. 1 - Functions155
- Ch. 2 - Limits and Continuity240
- Ch. 3 - Derivatives337
- Ch. 4 - Applications of Derivatives293
- Ch. 5 - Integrals41
- Ch. 6 - Applications of Definite Integrals25
- Ch. 7 - Transcendental Functions489
- Ch. 8 - Techniques of Integration398
- Ch. 9 - First-Order Differential Equations60
- Ch. 10 - Infinite Sequences and Series119
- Ch. 11 - Parametric Equations and Polar Coordinates58
Chapter 3, Problem 3.9.11
Linearization for Approximation
In Exercises 7–12, find a linearization at a suitably chosen integer near a at which the given function and its derivative are easy to evaluate.
f(x) = ∛x, a = 8.5
Verified step by step guidance1
Identify the function f(x) = ∛x and the point a = 8.5 where you want to approximate the function using linearization.
Choose a nearby integer to a = 8.5 where the function and its derivative are easy to evaluate. In this case, choose a = 8 because ∛8 is easy to compute.
Find the derivative of the function f(x) = ∛x. The derivative f'(x) can be found using the power rule for derivatives. Rewrite ∛x as x^(1/3) and differentiate: f'(x) = (1/3)x^(-2/3).
Evaluate the function and its derivative at the chosen integer a = 8. Calculate f(8) = ∛8 = 2 and f'(8) = (1/3)(8)^(-2/3).
Use the linearization formula L(x) = f(a) + f'(a)(x - a) to approximate the function near x = 8.5. Substitute the values found: L(x) = 2 + f'(8)(x - 8).
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Key Concepts
Here are the essential concepts you must grasp in order to answer the question correctly.
Linearization
Linearization is a method used to approximate a function near a given point using its tangent line. It involves finding the linear function that best approximates the original function at a specific point, typically where the function and its derivative are easy to evaluate. This technique simplifies complex functions into linear ones, making calculations more manageable.
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Linearization
Derivative
The derivative of a function represents the rate at which the function's value changes with respect to changes in its input. It is a fundamental concept in calculus used to find the slope of the tangent line at any point on the function. For linearization, the derivative is crucial as it provides the slope of the tangent line, which is used to construct the linear approximation.
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Choosing a Suitable Point
Choosing a suitable point near the given value is essential for effective linearization. This point should be an integer where the function and its derivative are easy to compute, ensuring the linear approximation is accurate and calculations are simplified. In this context, selecting a point like x = 8 for f(x) = ∛x allows for straightforward evaluation, as the cube root and its derivative are simple to calculate.
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Related Practice
Textbook Question
Find the derivatives of the functions in Exercises 1–42.
s = cos⁴ (1 - 2t)
Textbook Question
The diameter of a sphere is measured as 100 ± 1 cm and the volume is calculated from this measurement. Estimate the percentage error in the volume calculation.
Textbook Question
____
Find the linearization of ƒ(x) = 2/ (1 - x) + √1 + x - 3.1 at x = 0.
Textbook Question
Find the derivatives of the functions in Exercises 1–42.
𝔂 = 3 .
(5x² + sin 2x)³/²
Textbook Question
Find the derivatives of the functions in Exercises 1–42.
__
s = √ t .
1 + √ t