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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
All textbooksBriggs 3rd EditionCh. 5 - IntegrationProblem 5.3.107b
Chapter 5, Problem 5.3.107b

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.                                                                          
                                                                                                                                                                                     (b) Suppose Ζ’ is a negative increasing function, for 𝓍 > 0 . Then the area function A(𝓍) = βˆ«β‚€Λ£ Ζ’(t) dt is a decreasing function of 𝓍 .

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Step 1: Begin by understanding the problem statement. The function Ζ’(t) is given as a negative and increasing function for x > 0. This means that Ζ’(t) < 0 and its derivative Ζ’'(t) > 0 (since it is increasing). The area function A(x) is defined as A(x) = βˆ«β‚€Λ£ Ζ’(t) dt, which represents the accumulated area under the curve of Ζ’(t) from t = 0 to t = x.
Step 2: To determine whether A(x) is a decreasing function, compute the derivative of A(x) with respect to x. Using the Fundamental Theorem of Calculus, we know that A'(x) = Ζ’(x). This derivative tells us the rate of change of the area function A(x) with respect to x.
Step 3: Analyze the sign of A'(x). Since Ζ’(x) is negative for x > 0 (as given in the problem), A'(x) = Ζ’(x) is also negative. A negative derivative implies that the function A(x) is decreasing for x > 0.
Step 4: Consider the behavior of Ζ’(t) being an increasing function. Although Ζ’(t) is increasing, it remains negative for all x > 0. This means that while the rate at which A(x) decreases might slow down (due to Ζ’(t) becoming less negative), A(x) will still continue to decrease because Ζ’(x) < 0.
Step 5: Conclude that the statement is true. The area function A(x) = βˆ«β‚€Λ£ Ζ’(t) dt is indeed a decreasing function of x for x > 0, because its derivative A'(x) = Ζ’(x) is negative for all x > 0.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Definite Integral

A definite integral represents the signed area under a curve defined by a function over a specific interval. It is calculated using the Fundamental Theorem of Calculus, which connects differentiation and integration. The value of a definite integral can provide insights into the accumulation of quantities, such as area, volume, or total change, over the interval.
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Definition of the Definite Integral

Increasing and Decreasing Functions

A function is considered increasing on an interval if, for any two points within that interval, the function's value at the second point is greater than or equal to its value at the first point. Conversely, a function is decreasing if its value diminishes as the input increases. Understanding these properties is crucial for analyzing the behavior of functions and their integrals.
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Area Function

The area function A(x) = βˆ«β‚€Λ£ f(t) dt represents the accumulated area under the curve of the function f(t) from 0 to x. The behavior of this function can be influenced by the properties of f(t), such as whether it is positive or negative. In the case of a negative increasing function, the area function will decrease as x increases, reflecting the negative contributions to the area.
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Related Practice
Textbook Question

Area functions for the same linear function Let Ζ’(t) = t and consider the two area functions A(𝓍) = βˆ«β‚€Λ£ Ζ’(t) dt and F(𝓍) = βˆ«β‚‚Λ£ Ζ’(t) dt .

(b) Evaluate F(4) and F(6). Then use geometry to find an expression for F (𝓍) , for 𝓍 β‰₯ 2. 

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Textbook Question

Area functions for linear functions Consider the following functions Ζ’ and real numbers a (see figure).


b) Verify that A'(𝓍) = Ζ’(𝓍).



Ζ’(t) = 4t + 2 , a = 0

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Textbook Question

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample.

(a) If Ζ’ is symmetric about the line 𝓍 = 2 , then βˆ«β‚€β΄ Ζ’(𝓍) d𝓍 = 2 βˆ«β‚€Β² Ζ’(𝓍) d𝓍.

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Textbook Question

Use Table 5.6 to evaluate the following indefinite integrals.                                                                                                               

                                                                                                                                                                  

 (b) ∫ sec 5𝓍 tan 5𝓍 d𝓍

Textbook Question

Displacement from a velocity graph Consider the velocity function for an object moving along a line (see figure).

(b) Use geometry to find the displacement of the object between t = 0 and t = 2.

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Textbook Question

Matching functions with area functions Match the functions Ζ’, whose graphs are given in a― d, with the area functions A (𝓍) = βˆ«β‚€Λ£ Ζ’(t) dt, whose graphs are given in A–D.



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