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Ch. 5 - Integration
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
All textbooksBriggs 3rd EditionCh. 5 - IntegrationProblem 5.R.1a
Chapter 5, Problem 5.R.1a

Explain why or why not Determine whether the following statements are true and give an explanation or counterexample. Assume Ζ’ and Ζ’' are continuous functions for all real numbers.
(a) A(𝓍) = βˆ«β‚Λ£ Ζ’(t) dt and Ζ’(t) = 2t―3 , then A is a quadratic function.

Verified step by step guidance
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Step 1: Begin by recalling the Fundamental Theorem of Calculus, which states that if A(𝓍) = βˆ«β‚Λ£ Ζ’(t) dt, then A'(𝓍) = Ζ’(𝓍). This means the derivative of A(𝓍) is equal to the function Ζ’(𝓍).
Step 2: Analyze the given function Ζ’(t) = 2t - 3. This is a linear function because it is in the form of a first-degree polynomial (ax + b).
Step 3: Integrate Ζ’(t) = 2t - 3 with respect to t to find A(𝓍). The integral of 2t is tΒ², and the integral of -3 is -3t. Therefore, A(𝓍) = tΒ² - 3t + C, where C is the constant of integration.
Step 4: Observe that A(𝓍) = tΒ² - 3t + C is a quadratic function because it is in the form of a second-degree polynomial (axΒ² + bx + c). Quadratic functions are characterized by the presence of a squared term.
Step 5: Conclude that the statement is true because the integration of the linear function Ζ’(t) = 2t - 3 results in a quadratic function A(𝓍). The explanation is based on the properties of integration and the structure of the resulting polynomial.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Fundamental Theorem of Calculus

The Fundamental Theorem of Calculus links the concept of differentiation and integration, stating that if a function is continuous on an interval, then the integral of its derivative over that interval gives the net change of the function. This theorem allows us to evaluate definite integrals and understand the relationship between a function and its antiderivative.
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Fundamental Theorem of Calculus Part 1

Definite Integral

A definite integral represents the accumulation of quantities, such as area under a curve, over a specific interval. It is denoted as βˆ«β‚Λ£ Ζ’(t) dt, where 'a' and 'x' are the limits of integration. The result of a definite integral is a number that quantifies the total accumulation of the function Ζ’(t) from 'a' to 'x'.
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Quadratic Functions

A quadratic function is a polynomial function of degree two, typically expressed in the form f(x) = axΒ² + bx + c, where a, b, and c are constants and a β‰  0. The graph of a quadratic function is a parabola, which can open upwards or downwards depending on the sign of 'a'. Understanding the properties of quadratic functions is essential for determining the nature of the function A(x) in the given problem.
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Related Practice
Textbook Question

Area versus net area Find (i) the net area and (ii) the area of the region bounded by the graph of Ζ’ and the 𝓍-axis on the given interval. You may find it useful to sketch the region.

Ζ’(𝓍) = 𝓍⁴ ― 𝓍² on [―1, 1]

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Textbook Question

Function defined by an integral Let H (𝓍) = βˆ«β‚€Λ£ √(4 ― tΒ²) dt, for ― 2 ≀ 𝓍 ≀ 2.

(a) Evaluate H (0) .

Textbook Question

Find the average value of Ζ’(𝓍) = eΒ²Λ£ on [0, ln 2] .

Textbook Question

Evaluating integrals Evaluate the following integrals.


βˆ«β‚€ΒΉ 𝓍 β€’ 2ˣ²⁺¹ d𝓍

Textbook Question

Evaluating integrals Evaluate the following integrals.


βˆ«β‚€ΒΉ βˆšπ“ (βˆšπ“ + 1) d𝓍

Textbook Question

Properties of integrals Suppose βˆ«β‚β΄ Ζ’(𝓍) d𝓍 = 6 , βˆ«β‚β΄ g(𝓍) d𝓍 = 4 and βˆ«β‚ƒβ΄ Ζ’(𝓍) d𝓍 = 2 . Evaluate the following integrals or state that there is not enough information.


βˆ«β‚Β³ Ζ’(𝓍)/g(𝓍) d𝓍