Ch. 5 - Integration

Briggs - Calculus: Early Transcendentals 3rd Edition

Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook

Briggs 3rd Edition

Ch. 5 - Integration

Problem 5.1.19

Chapter 5, Problem 5.1.19

Approximating displacement The velocity of an object is given by the following functions on a specified interval. Approximate the displacement of the object on this interval by subdividing the interval into n subintervals. Use the left endpoint of each subinterval to compute the height of the rectangles.
v = [1 / (2t + 1)] (m/s), for 0 ≤ t ≤ 8 ; n = 4

Verified step by step guidance

Step 1: Understand the problem. The goal is to approximate the displacement of the object over the interval [0, 8] using the velocity function v = 1 / (2t + 1). The interval is subdivided into n = 4 subintervals, and the left endpoint of each subinterval is used to compute the height of the rectangles.

Step 2: Determine the width of each subinterval. The interval [0, 8] is divided into n = 4 subintervals, so the width of each subinterval (Δt) is calculated as Δt = (8 - 0) / 4 = 2.

Step 3: Identify the left endpoints of each subinterval. Since the interval is divided into 4 subintervals of width 2, the left endpoints are t = 0, t = 2, t = 4, and t = 6.

Step 4: Compute the height of each rectangle using the velocity function at the left endpoints. For each left endpoint t_i, calculate v(t_i) = 1 / (2t_i + 1). Specifically, compute v(0), v(2), v(4), and v(6).

Step 5: Approximate the displacement by summing the areas of the rectangles. The area of each rectangle is given by height × width = v(t_i) × Δt. Add these areas together to approximate the total displacement: Displacement ≈ Δt × [v(0) + v(2) + v(4) + v(6)].

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Velocity and Displacement

Velocity is the rate of change of displacement with respect to time, indicating how fast an object moves in a specific direction. Displacement, on the other hand, is the total distance moved in a particular direction over a given time interval. Understanding the relationship between velocity and displacement is crucial for approximating the total displacement of an object over a specified time period.

Riemann Sums

Riemann sums are a method for approximating the integral of a function, which in this context helps estimate the total displacement. By dividing the interval into smaller subintervals and using the left endpoint of each subinterval to determine the height of rectangles, we can sum the areas of these rectangles to approximate the integral. This technique is foundational in calculus for understanding how to calculate areas under curves.

Subintervals and Partitioning

Partitioning an interval into subintervals involves dividing the total time interval into smaller segments, which allows for more accurate approximations of the function's behavior. In this case, with n = 4, the interval from 0 to 8 is divided into four equal parts. This subdivision is essential for applying Riemann sums effectively, as it determines how the function is sampled and influences the accuracy of the displacement approximation.

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Related Practice

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Textbook Question

Approximating displacement The velocity of an object is given by the following functions on a specified interval. Approximate the displacement of the object on this interval by subdividing the interval into n subintervals. Use the left endpoint of each subinterval to compute the height of the rectangles.

v = 2t + 1(m/s), for 0 ≤ t ≤ 8 ; n = 2

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Textbook Question

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