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Ch. 3 - Derivatives
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 3, Problem 3.43c

City urbanization City planners model the size of their city using the function A(t) = - 1/50t² + 2t +20, for 0 ≤ t ≤ 50, where A is measured in square miles and t is the number of years after 2010.
c. Suppose the population density of the city remains constant from year to year at 1000 people mi². Determine the growth rate of the population in 2030.

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Step 1: Identify the function that models the size of the city. The function given is A(t) = -\(\frac{1}{50}\)t^2 + 2t + 20, where A is the area in square miles and t is the number of years after 2010.
Step 2: Determine the year 2030 in terms of t. Since t is the number of years after 2010, for the year 2030, t = 2030 - 2010 = 20.
Step 3: Find the derivative of A(t) with respect to t to determine the rate of change of the area. The derivative, A'(t), represents the growth rate of the city's area in square miles per year.
Step 4: Calculate A'(t) by differentiating A(t). A'(t) = \(\frac{d}{dt}\)(-\(\frac{1}{50}\)t^2 + 2t + 20) = -\(\frac{1}{25}\)t + 2.
Step 5: Evaluate A'(t) at t = 20 to find the growth rate of the city's area in 2030. Then, multiply this rate by the population density (1000 people/mi²) to find the growth rate of the population.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Function Analysis

Understanding the function A(t) = -1/50t² + 2t + 20 is crucial for analyzing the area of the city over time. This quadratic function represents a parabolic curve, where the coefficients indicate how the area changes with respect to time. The vertex of the parabola will provide insights into the maximum area, while evaluating the function at specific values of t will yield the area at those years.
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Population Density

Population density is defined as the number of people per unit area, in this case, 1000 people per square mile. This constant density allows us to calculate the total population by multiplying the area of the city A(t) by the density. Understanding this relationship is essential for determining how the population grows as the area of the city changes over time.
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Rate of Change

The growth rate of the population can be determined by finding the derivative of the area function A(t) with respect to time t. This derivative, A'(t), gives the instantaneous rate of change of the area, which, when multiplied by the constant population density, will yield the growth rate of the population. Evaluating this derivative at t = 20 (for the year 2030) will provide the specific growth rate at that time.
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Related Practice
Textbook Question

Highway travel A state patrol station is located on a straight north-south freeway. A patrol car leaves the station at 9:00 A.M. heading north with position function s = f(t) that gives its location in miles t hours after 9:00 A.M. (see figure). Assume s is positive when the car is north of the patrol station. <IMAGE>

c. Find the average velocity of the car over the interval [1.75, 2.25]. Estimate the velocity of the car at 11:00 A.M. and determine the direction in which the patrol car is moving.

Textbook Question

62–65. {Use of Tech} Graphing f and f'

c. Verify that the zeros of f' correspond to points at which f has a horizontal tangent line.

f(x)=e^−x tan^−1 x on [0,∞)

Textbook Question

Deriving trigonometric identities

c. Differentiate both sides of the identity sin 2t = 2 sin t cost to prove that cos 2t = cos²t−sin²t.

Textbook Question

Throwing a stone Suppose a stone is thrown vertically upward from the edge of a cliff on Earth with an initial velocity of 32 ft/s from a height of 48 ft above the ground. The height (in feet) of the stone above the ground t seconds after it is thrown is s(t) = -16t²+32t+48.

c. What is the height of the stone at the highest point?

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Textbook Question

Vibrations of a spring Suppose an object of mass m is attached to the end of a spring hanging from the ceiling. The mass is at its equilibrium position y=0y=0 when the mass hangs at rest. Suppose you push the mass to a position y0y_0 units above its equilibrium position and release it. As the mass oscillates up and down (neglecting any friction in the system), the position y of the mass after t seconds is y=y0cos(tkm)y=y_0\(\cos\]\left\)(t\(\sqrt{\frac{k}{m}\)}\(\right\)), where k>0k>0 is a constant measuring the stiffness of the spring (the larger the value of kk, the stiffer the spring) and yy is positive in the upward direction.

Use equation (4) to answer the following questions.

c. How would the velocity be affected if the experiment were repeated with a spring having four times the stiffness (kk is increased by a factor of 44)?

Textbook Question

Finding derivatives from a table Find the values of the following derivatives using the table. <IMAGE>


c. d/dx ((f(x)g(x)) |x=3

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