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Ch. 2 - Limits
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 2, Problem 2.6.29

Determine the interval(s) on which the following functions are continuous. 
f(x)=1 / x^2−4

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Identify the type of function: \( f(x) = \frac{1}{x^2 - 4} \) is a rational function, which is continuous everywhere in its domain.
Determine where the denominator is zero: Set \( x^2 - 4 = 0 \) and solve for \( x \).
Solve the equation: \( x^2 - 4 = 0 \) can be factored as \( (x - 2)(x + 2) = 0 \), giving solutions \( x = 2 \) and \( x = -2 \).
Identify the points of discontinuity: The function is discontinuous at \( x = 2 \) and \( x = -2 \) because the denominator is zero at these points.
Determine the intervals of continuity: The function is continuous on the intervals \((-\infty, -2)\), \((-2, 2)\), and \((2, \infty)\).

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Continuity of Functions

A function is continuous at a point if the limit of the function as it approaches that point equals the function's value at that point. For a function to be continuous over an interval, it must be continuous at every point within that interval. This means there are no breaks, jumps, or asymptotes in the function's graph.
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Intro to Continuity

Identifying Discontinuities

Discontinuities in a function can occur at points where the function is undefined, such as division by zero. For the function f(x) = 1 / (x^2 - 4), we need to find values of x that make the denominator zero, as these points will indicate where the function is discontinuous. In this case, x^2 - 4 = 0 leads to x = ±2.
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Intro to Continuity Example 1

Intervals of Continuity

Once discontinuities are identified, the next step is to determine the intervals where the function remains continuous. For f(x) = 1 / (x^2 - 4), the function is continuous on the intervals that do not include the points of discontinuity. Thus, the intervals of continuity for this function are (-∞, -2) and (-2, 2) and (2, ∞).
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Intro to Continuity Example 1
Related Practice
Textbook Question

Use the precise definition of a limit to prove the following limits. Specify a relationship between ε and δ that guarantees the limit exists.

lim x→1 x^4=1

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Textbook Question

Sketch the graph of a function with the given properties. You do not need to find a formula for the function. 


p(0) = 2,lim x→0 p(x) = 0,lim x→2 p(x) does not exist, p(2)=lim x→2^+ p(x)=1

Textbook Question

Determine the following limits.

lim θ→π/2 sin^2 θ − 5 sin θ + 4 / sin^2 θ − 1

Textbook Question

If a function f represents a system that varies in time, the existence of lim limtf(t){\(\displaystyle\[\lim\)_{t\(\rightarrow\]\infty\)}{f(t)}} means that the system reaches a steady state (or equilibrium). For the following systems, determine whether a steady state exists and give the steady-state value.


The population of a bacteria culture is given by p(t)=2500t+1p\(\left\)(t\(\right\))=\(\frac{2500}{t+1}\).

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Textbook Question

Find an interval containing a solution to the equation 2x=cos(x)2x=\(\cos\]\left\)(x\(\right\)). Use a graphing utility to approximate the solution.

Textbook Question

Find all vertical asymptotes x=ax=a of the following functions. For each value of aa, determine limxa+f(x){\(\displaystyle\]\lim\)_{x\(\to\) a^{+}}}f\(\left\)(x\(\right\)), limxaf(x){\(\displaystyle\]\lim\)_{x\(\to\) a^{-}}}f\(\left\)(x\(\right\)), and limxaf(x){\(\displaystyle\]\lim\)_{x\(\to\) a}}f\(\left\)(x\(\right\)).

f(x)=cos(x)x2+2xf\(\left\)(x\(\right\))=\(\frac{\cos\left(x\right)}{x^2+2x}\)