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Ch. 11 - Power Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 11, Problem 11.1.85

{Use of Tech} Approximating sin x Let f(x)=sin x, and let pₙ and qₙ be nth−order Taylor polynomials for f centered at 0 and π, respectively.
a. Find p₅ and q₅
b. Graph f, p₅, and q₅ on the interval [−π, 2π]. On what interval is p₅ a better approximation to f than q₅? On what interval is q₅ a better approximation to f than p₅?
c. Complete the following table showing the errors in the approximations given by p₅ and q₅ at selected points.
Table comparing errors of fifth-order Taylor polynomial approximations of sin x at selected x values.
d. At which points in the table is p₅ a better approximation to f than q₅? At which points do p₅ and q₅ give equal approximations to f? Explain your observations.

Verified step by step guidance
1
Step 1: Find the fifth-order Taylor polynomial \(p_5(x)\) for \(f(x) = \sin x\) centered at 0. Recall that the Taylor series for \(\sin x\) at 0 is \(\sin x = \sum_{n=0}^\infty (-1)^n \frac{x^{2n+1}}{(2n+1)!}\). The fifth-order polynomial includes terms up to \(x^5\), so write out \(p_5(x) = x - \frac{x^3}{3!} + \frac{x^5}{5!}\).
Step 2: Find the fifth-order Taylor polynomial \(q_5(x)\) for \(f(x) = \sin x\) centered at \(\pi\). To do this, compute the derivatives of \(\sin x\) at \(x=\pi\) up to the fifth derivative, then use the Taylor polynomial formula centered at \(\pi\): \(q_5(x) = \sum_{n=0}^5 \frac{f^{(n)}(\pi)}{n!} (x - \pi)^n\). Write out the polynomial explicitly by substituting the values of the derivatives.
Step 3: To compare the approximations, graph \(f(x) = \sin x\), \(p_5(x)\), and \(q_5(x)\) on the interval \([-\pi, 2\pi]\). Observe where each polynomial closely follows the sine curve. The polynomial centered at 0 (\(p_5\)) will approximate better near 0, and the polynomial centered at \(\pi\) (\(q_5\)) will approximate better near \(\pi\). Identify the intervals where each polynomial is a better approximation by visually comparing the graphs.
Step 4: Complete the error table by calculating the absolute errors \(|\sin x - p_5(x)|\) and \(|\sin x - q_5(x)|\) at the given points \(x = \frac{\pi}{4}, \frac{\pi}{2}, \frac{3\pi}{4}, \frac{5\pi}{4}, \frac{7\pi}{4}\). For each \(x\), evaluate \(p_5(x)\) and \(q_5(x)\) using the polynomials found in steps 1 and 2, then subtract from \(\sin x\) and take the absolute value.
Step 5: Analyze the completed table to determine at which points \(p_5\) is a better approximation (smaller error) than \(q_5\), and vice versa. Also, identify any points where the errors are equal. Explain these observations in terms of the distance of each \(x\) value from the centers 0 and \(\pi\), since Taylor polynomials approximate best near their center points.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Taylor Polynomials

Taylor polynomials approximate functions near a specific point using derivatives at that point. The nth-order Taylor polynomial of a function f centered at a point a uses derivatives up to order n to create a polynomial that closely matches f near a. For example, p₅ is the 5th-order Taylor polynomial of sin x centered at 0.
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Error in Taylor Polynomial Approximation

The error between a function and its Taylor polynomial approximation measures how closely the polynomial matches the function. It is given by the absolute difference |f(x) - pₙ(x)|. Understanding this error helps determine the interval where the approximation is accurate and which polynomial (p₅ or q₅) better approximates the function at different points.
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Interval of Convergence and Approximation Accuracy

Taylor polynomials approximate functions best near their center of expansion. The interval of convergence is where the polynomial closely matches the function. For p₅ centered at 0 and q₅ centered at π, each polynomial will better approximate sin x near its center, and the graph and error table help identify these intervals.
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