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Ch. 11 - Power Series
Briggs - Calculus: Early Transcendentals 3rd Edition
Briggs3rd EditionCalculus: Early TranscendentalsISBN: 9780136847243Not the one you use?Change textbook
Chapter 11, Problem 11.3.11a

Taylor series and interval of convergence


a. Use the definition of a Taylor/Maclaurin series to find the first four nonzero terms of the Taylor series for the given function centered at a.


f(x) = e⁻ˣ, a=0

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1
Recall that the Maclaurin series is a Taylor series centered at \(a=0\), and is given by the formula: \[f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(0)}{n!} x^n,\] where \(f^{(n)}(0)\) is the \(n\)-th derivative of \(f\) evaluated at 0.
Find the first few derivatives of the function \(f(x) = e^{-x}\). Note the pattern of the derivatives: - \(f(x) = e^{-x}\) - \(f'(x) = -e^{-x}\) - \(f''(x) = e^{-x}\) - \(f^{(3)}(x) = -e^{-x}\) - \(f^{(4)}(x) = e^{-x}\) and so on, alternating signs.
Evaluate each derivative at \(x=0\): - \(f(0) = e^{0} = 1\) - \(f'(0) = -e^{0} = -1\) - \(f''(0) = e^{0} = 1\) - \(f^{(3)}(0) = -e^{0} = -1\) - \(f^{(4)}(0) = e^{0} = 1\)
Write the first four nonzero terms of the Maclaurin series using the formula: \[\frac{f(0)}{0!} x^0 + \frac{f'(0)}{1!} x^1 + \frac{f''(0)}{2!} x^2 + \frac{f^{(3)}(0)}{3!} x^3.\] Substitute the values found in the previous step.
Simplify each term by calculating the factorial in the denominator and write the series terms explicitly, keeping the alternating signs and powers of \(x\) clear.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Taylor and Maclaurin Series Definition

A Taylor series represents a function as an infinite sum of terms calculated from the derivatives of the function at a single point. When centered at zero, it is called a Maclaurin series. Each term involves the nth derivative evaluated at the center, multiplied by (x - a)^n and divided by n!.
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Convergence of Taylor & Maclaurin Series

Derivatives of Exponential Functions

Understanding how to compute derivatives of exponential functions like e^(-x) is essential. The derivative of e^(-x) involves the chain rule, resulting in factors of -1 raised to the power of the derivative order, which affects the sign and form of each term in the series.
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Interval of Convergence

The interval of convergence is the set of x-values for which the Taylor series converges to the function. For exponential functions, the series often converges for all real numbers, but determining this interval ensures the series accurately represents the function within that domain.
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Interval of Convergence