find-the-sum-of-the-infinite-series-j165j65j1displaystylesumj1infty-left-frac65j

Question

Find the sum of the infinite series ∑j=1∞(65j−65j+1)\displaystyle\sum_{j=1}^{\infty} \left( \frac{6}{5^j} - \frac{6}{$$5^{j+1}$$} \right)  using a telescoping series argument.

Accepted Answer

65\frac65

Answer

35\frac35

Answer

625\frac{6}{25}

Answer

47\frac47

Find the sum of the infinite series ∑j=1∞(65j−65j+1)\(\displaystyle\]\sum\)_{j=1}^{\(\infty\)} \(\left\)( \(\frac{6}{5^j}\) - \(\frac{6}{5^{j+1}\)} \(\right\)) using a telescoping series argument.

Find the sum of the infinite series $\sum_{j = 1}^{\infty} (\frac{6}{5^{j}} - \frac{6}{5^{j + 1}})$ using a telescoping series argument.