find-the-limit-of-the-sequence-bn-frac5n4-23n4-7-as-n-to-infty

Question

Find the limit of the sequence bn=5n4+23n4−7 b_n = \frac{$$5n^4 + 2$$}{$$3n^4 - 7$$}  as n→∞ n 	o \infty .

Accepted Answer

53\frac53

Answer

35\frac35

Answer

00

Answer

∞\infty

Find the limit of the sequence bn=5n4+23n4−7 b_n = \(\frac{5n^4 + 2}{3n^4 - 7}\) as n→∞ n \(\to\) \(\infty\) .