find-the-explicit-general-solution-to-s232uussu216-s2-32-u-uprimes-s-u2-16

Question

Find the explicit general solution to (s2+3)2uu′(s)=s(u2+16) $$(s^2$$ + $$3)^2 u$$ $$u^{\prime}(s) = s$$ $$(u^2 + 16) .$$

Accepted Answer

u(s)=±Ae−1s2+3−16u(s)=\pm\sqrt{A $$e^{-\frac{1}$${$$s^2 + 3$$}} - 16}

Answer

u(s)=±Ae1s2+3−16u(s)=\pm\sqrt{$$Ae^{\frac{1}$${$$s^2 + 3$$}}-16}

Answer

u(s)=±Ae−1s2+3+16u(s)=\pm\sqrt{$$Ae^{-\frac{1}$${$$s^2 + 3$$}}+16}

Answer

u(s)=Ae−1s2+3−16u(s)=\sqrt{A $$e^{-\frac{1}$${$$s^2 + 3$$}} - 16}

Find the explicit general solution to (s2+3)2uu′(s)=s(u2+16) (s^2 + 3)^2 u u^{\(\prime\)}(s) = s (u^2 + 16) .