Given the parametric equations $x=3t$ and $y=2t+1$, for $-6\le t\le 6$, eliminate the parameter to find an equation relating $x$ and $y$. Then, describe the curve represented by this equation.

$y=\frac{2}{3}x+1$

Line segment from $(-18,-11)$ to $(18,13)$, traced in that order as $t$ increases from $-6$ to $6$

$y=\frac{2}{3}x+1$

Line segment from $(18,13)$ to $(-18,-11)$, traced in that order as $t$ increases from $-6$ to $6$

$y=\frac{2}{3}{x}^2-1$

Parabola opening upward from $(-3,7)$ to $(3,7)$, traced in that order as $t$ increases from $-6$ to $6$

$y=\frac{2}{3}{x}^2-1$

Parabola opening upward from $(3,7)$ to $(-3,7)$, traced in that order as $t$ increases from $-6$ to $6$