A drone with a mass of $1.5\text{ kg}$ descends vertically with air resistance proportional to the square of its velocity ($k=0.05$). The distance it descends (in meters) after $t$ seconds is given by $s\left(t\right)=\frac{m}{k}\ln \left(\cosh \left(\sqrt{\frac{kg}{m}}t\right)\right)$. How far does the drone descend in $6$ seconds? Use $g=9.8{\text{ m/s}}^2$. Round the answer to one decimal place.