for-the-following-trigonometric-equation-find-the-radian-measure-of-aa-in-terms-

Question

For the following trigonometric equation, find the radian measure of AA in terms of π\pi.sin⁡(2A)=cos⁡(2A),0≤A2π\sin\left(2A\right)=\cos\left(2A\right),0\leq{A}\lt{2\pi}

Accepted Answer

{π8,5π8,9π8,13π8}\left\lbrace\frac{\pi}{8},\frac{5\pi}{8},\frac{9\pi}{8},\frac{13\pi}{8}\right\rbrace

Answer

{π4,5π4,9π4,13π4}\left\lbrace\frac{\pi}{4},\frac{5\pi}{4},\frac{9\pi}{4},\frac{13\pi}{4}\right\rbrace

Answer

{π8,5π8}\left\lbrace\frac{\pi}{8},\frac{5\pi}{8}\right\rbrace

Answer

{π4,5π4}\left\lbrace\frac{\pi}{4},\frac{5\pi}{4}\right\rbrace

For the following trigonometric equation, find the radian measure of AA in terms of π\(\pi\).sin(2A)=cos(2A),0≤A<2π\(\sin\]\left\)(2A\(\right\))=\(\cos\[\left\)(2A\(\right\)),0\(\leq{A}\]\lt{2\pi}\)

For the following trigonometric equation, find the radian measure of $A$ in terms of $π$ .
$sine 2 A equals cosine 2 A comma 0 is less than or equal to A is less than 2 pi$