use-a-table-of-integrals-to-evaluate-the-definite-integral-48d-yyy216int48fracdy

Question

Use a table of integrals to evaluate the definite integral:∫48d yyy2−16\$$int_4^8$$\frac{d\,y}{y\sqrt{$$y^2 - 16$$}}

Accepted Answer

π12\frac{\pi}{12}

Answer

π2\frac{\pi}{2}

Answer

π3\frac{\pi}{3}

Answer

π4\frac{\pi}{4}

Use a table of integrals to evaluate the definite integral:∫48dyyy2−16\(\int\)_4^8\(\frac{d\,y}{y\sqrt{y^2 - 16}\)}