Calculus
What is the integral of 1/√(1 - x^2) dx?
What is the integral of 1/(1 + x^2) dx?
Evaluate ∫ 1/x^2 dx using the power rule.
Use a table of integrals to evaluate the definite integral:
∫48dyyy2−16\(\int\)_4^8\(\frac{d\,y}{y\sqrt{y^2 - 16}\)}
Evaluate the integral: ∫dxx2−25\(\int\]\frac{dx}{\sqrt{x^2 - 25}\)}, x>5x>5