let-yx32x3et-dt-y-intx32x3-et-dt-find-dydx-fracdydx

Question

Let y=∫x32x3et dt\displaystyle y=\int_{$$x^3$$}^{$$2x^3$$}$$e^{t}$$\,dt. Find dydx\displaystyle\frac{dy}{dx}.

Accepted Answer

6x2e2x3−3x2ex3 $$6x^2$$ $$e^{2x^3}$$ - $$3x^2$$ $$e^{x^3}$$

Answer

2x3e2x3−x3ex3 $$2x^3$$ $$e^{2x^3}$$ - $$x^3$$ $$e^{x^3}$$

Answer

6x2e2x3+3x2ex3 $$6x^2$$ $$e^{2x^3}$$ + $$3x^2$$ $$e^{x^3}$$

Answer

2x3e2x3+x3ex3 $$2x^3$$ $$e^{2x^3}$$ + $$x^3$$ $$e^{x^3}$$

Let y=∫x32x3etdt\(\displaystyle\) y=\(\int\)_{x^3}^{2x^3}e^{t}\,dt. Find dydx\(\displaystyle\]\frac{dy}{dx}\).