Calculus
uk+1=1+(k+1)2ah3k{\(\displaystyle\)\,u_{k+1}=1+\(\frac{(k+1)}{2}\)ah^3k\,}
uk+1=1+(k+1)(2k+1)6ah3k{\(\displaystyle\)\,u_{k+1}=1+\(\frac{(k+1)(2k+1)}{6}\)ah^3k\,}
uk+1=1+(k+1)(k+2)6ahk{\(\displaystyle\)\,u_{k+1}=1+\(\frac{(k+1)(k+2)}{6}\)ahk\,}
uk+1=(k+1)(k+2)6ah3k{{\(\displaystyle\)\,u_{k+1}=\(\frac{(k+1)(k+2)}{6}\)ah^3k\,}}