find-the-equation-of-the-tangent-line-to-the-curve-x28y-x2-8y-at-the-point-42-4-

Question

Find the equation of the tangent line to the curve x2=8y $$x^2 = 8y  at $$the point (4,2) (4, 2) .

Accepted Answer

y=x−2y=x-2

Answer

y=2x−1y=2x-1

Answer

y=2−xy=2-x

Answer

y=x+2y=x+2

Find the equation of the tangent line to the curve x2=8y x^2 = 8y at the point (4,2) (4, 2) .