Calculus
33−π3+π3\(\dfrac{3\sqrt{3}\)-\(\pi\)}{3+\(\pi\]\sqrt{3}\)}
3+π1−π3\(\displaystyle\[\frac{\sqrt{3}\)+\(\pi\)}{1-\(\pi\]\sqrt{3}\)}
33+π3−π3\(\dfrac{3\sqrt{3}\)+\(\pi\)}{3-\(\pi\]\sqrt{3}\)}
3+π3−π\(\dfrac{\sqrt{3}\)+\(\pi\)}{3-\(\pi\)}