a-bacteria-culture-grows-according-to-bt05b1b2000bprimet05bleft1-fracb2000right-

Question

A bacteria culture grows according to B′(t)=0.5B(1−$$B2000)B^{\prime}(t)=0.5B$$\left(1-\frac{B}{2000}\right). What are the equilibrium solutions?

Accepted Answer

B(t)=0B(t)=0B(t)=2000B(t)=2000

Answer

B(t)=0B(t)=0B(t)=−2000B(t)=-2000

Answer

B(t)=0B(t)=0B(t)=12000B(t)=\frac{1}{2000}

Answer

B(t)=1B(t)=1B(t)=2000B(t)=2000

A bacteria culture grows according to B′(t)=0.5B(1−B2000)B^{\(\prime\)}(t)=0.5B\(\left\)(1-\(\frac{B}{2000}\]\right\)). What are the equilibrium solutions?