suppose-k112xk18-displaystyle-sumk112-xk-18-k112xk18-and-k112yk7-displaystyle-su

Question

Suppose ∑k=112xk=18\displaystyle\sum_{k=1}^{12} x_k = 18 and ∑k=112yk=−7\displaystyle\sum_{k=1}^{12} y_k = -7. Compute the value of ∑k=112(xk−yk+3){\displaystyle\sum_{k=1}^{12}\bigl(x_{k}-y_{k}+3\bigr)}.

Accepted Answer

6161

Answer

1414

Answer

2828

Answer

3434

Suppose ∑k=112xk=18\(\displaystyle\)\(\sum\)_{k=1}^{12} x_k = 18 and ∑k=112yk=−7\(\displaystyle\)\(\sum\)_{k=1}^{12} y_k = -7. Compute the value of ∑k=112(xk−yk+3){\(\displaystyle\)\(\sum\)_{k=1}^{12}\(\bigl\)(x_{k}-y_{k}+3\(\bigr\))}.

Suppose $\sum_{k = 1}^{12} x_{k} = 18$ and $\sum_{k = 1}^{12} y_{k} = - 7$ . Compute the value of $\sum_{k = 1}^{12} (x_{k} - y_{k} + 3)$ .