find-the-equation-of-the-tangent-line-to-the-curve-x225y291displaystylefracx225f

Question

Find the equation of the tangent line to the curve x225+y29=1\displaystyle\frac{$$x^{2}$$}{25}+\frac{$$y^{2}$$}{9}=1 at the point (4,95)\displaystyle\left(4,\frac95\right). Write your answer in slope-intercept form.

Accepted Answer

y=−45x+5\displaystyle y = -\frac{4}{5} x + 5

Answer

y=−54x+5{\displaystyle y=-\frac54x+5}

Answer

y=−45x−5{\displaystyle y=-\frac{4}{5}x-5}

Answer

y=45x+5{\displaystyle y=\frac{4}{5}x+5}

Find the equation of the tangent line to the curve x225+y29=1\(\displaystyle\]\frac{x^{2}\)}{25}+\(\frac{y^{2}\)}{9}=1 at the point (4,95)\(\displaystyle\]\left\)(4,\(\frac\)95\(\right\)). Write your answer in slope-intercept form.

Find the equation of the tangent line to the curve $\frac{x^{2}}{25} + \frac{y^{2}}{9} = 1$ at the point $open paren 4 comma nine fifths close paren$ . Write your answer in slope-intercept form.