express-the-left-hand-side-of-the-equation-x2-yx-2x-yx-frac2x-1x-as-the-derivati

Question

Express the left-hand side of the equation x2y′(x)+2xy(x)=$$2x+1xx^2$y^{\prime}(x)+2xy(x$$)=\frac{2x + 1}{x} as the derivative of a single term, and solve the initial value problem given that y(1)=4 y(1) = 4 .

Accepted Answer

y(x)=2x+ln⁡∣x∣+2x2y(x)=\frac{2x + \ln|x| + 2}{$$x^2$$}

Answer

y(x)=x+2ln⁡∣x∣+3x2y(x)=\frac{x+2\ln|x|+3}{$$x^2$$}

Answer

y(x)=x+2ln⁡∣x∣+1x2y(x)=\frac{x+2\ln|x|+1}{$$x^2$$}

Answer

y(x)=2x+ln⁡∣x∣+1xy(x)=\frac{2x+\ln|x|+1}{x}

Express the left-hand side of the equation x2y′(x)+2xy(x)=2x+1xx^2y^{\(\prime\)}(x)+2xy(x)=\(\frac{2x + 1}{x}\) as the derivative of a single term, and solve the initial value problem given that y(1)=4 y(1) = 4 .

Express the left-hand side of the equation $x^{2} y^{'} (x) + 2 x y (x) = \frac{2 x + 1}{x}$ as the derivative of a single term, and solve the initial value problem given that $y of 1 equals 4$ .