Ch. 4 - Applications of Derivatives

Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook

Hass 15th Edition

Ch. 4 - Applications of Derivatives

Problem 4.4.93

Chapter 4, Problem 4.4.93

93. The accompanying figure shows a portion of the graph of a twice-differentiable function y=f(x). At each of the five labeled points, classify y' and \(\y\)'' as positive, negative, or zero.

Verified step by step guidance

Step 1: Understand the problem. The graph represents a twice-differentiable function y = f(x). At each labeled point (P, Q, R, S, T), we need to classify the first derivative (y') and the second derivative (y'') as positive, negative, or zero based on the behavior of the graph.

Step 2: Analyze point P. At P, the graph is decreasing (sloping downward), so y' < 0. The graph is concave down (curving downward), so y'' < 0.

Step 3: Analyze point Q. At Q, the graph is at a local minimum, meaning the slope is zero (y' = 0). The graph transitions from concave down to concave up, so y'' > 0.

Step 4: Analyze point R. At R, the graph is increasing (sloping upward), so y' > 0. The graph is concave up (curving upward), so y'' > 0.

Step 5: Analyze point S. At S, the graph is at a local maximum, meaning the slope is zero (y' = 0). The graph transitions from concave up to concave down, so y'' < 0.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

First Derivative (y')

The first derivative of a function, y', represents the slope of the tangent line to the graph at any given point. It indicates the rate of change of the function. If y' is positive, the function is increasing; if y' is negative, the function is decreasing; and if y' is zero, the function has a horizontal tangent, indicating a potential local maximum or minimum.

Second Derivative (y'')

The second derivative, y'', provides information about the concavity of the function. If y'' is positive, the graph is concave up, resembling a 'U' shape, indicating that the slope of the tangent line is increasing. If y'' is negative, the graph is concave down, resembling an 'n' shape, indicating that the slope of the tangent line is decreasing. A zero value for y'' may indicate an inflection point where the concavity changes.

Critical Points and Inflection Points

Critical points occur where the first derivative y' is zero or undefined, often corresponding to local maxima or minima. Inflection points occur where the second derivative y'' is zero or changes sign, indicating a change in concavity. Analyzing these points helps in understanding the behavior of the function and its graph, such as identifying peaks, troughs, and points of curvature change.

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Critical Points

Related Practice

Textbook Question

Each of Exercises 67–88 gives the first derivative of a continuous function y=f(x). Find y'' and then use Steps 2–4 of the graphing procedure described in this section to sketch the general shape of the graph of f.

85. y' = x^(-2/3) (x - 1)

Textbook Question

Finding Indefinite Integrals

In Exercises 17–56, find the most general antiderivative or indefinite integral. You may need to try a solution and then adjust your guess. Check your answers by differentiation.

∫(1/x² − x² − 1/3) dx

Textbook Question

35. Determine the dimensions of the rectangle of largest area that can be inscribed in the right triangle shown in the accompanying figure.

Textbook Question

Finding Critical Points

In Exercises 41–50, determine all critical points and all domain endpoints for each function.

f(x) = x(4 − x)³

Textbook Question

Estimate the open intervals on which the function y = ƒ(𝓍) is

a. increasing.

b. decreasing.

c. Use the given graph of ƒ' to indicate where any local extreme