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Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 8, Problem 8.PE.111

Evaluate the integrals in Exercises 69–134. The integrals are listed in random order so you need to decide which integration technique to use.
∫₁^∞ (lny) / y³ dy

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1
Identify the integral to evaluate: \(\int_1^{\infty} \frac{\ln y}{y^3} \, dy\). Notice that the integral has an infinite upper limit, so this is an improper integral and we will need to check for convergence after finding the antiderivative.
Consider using integration by parts since the integrand is a product of \(\ln y\) and \(y^{-3}\). Let \(u = \ln y\) (which simplifies upon differentiation) and \(dv = y^{-3} dy\) (which is straightforward to integrate).
Compute the derivatives and antiderivatives for integration by parts: \(du = \frac{1}{y} dy\) and \(v = \int y^{-3} dy = \int y^{-3} dy = -\frac{1}{2} y^{-2}\).
Apply the integration by parts formula: \(\int u \, dv = uv - \int v \, du\). Substitute the expressions for \(u\), \(v\), \(du\) to write the integral in terms of simpler integrals.
Evaluate the resulting integral and then apply the limits from 1 to \(\infty\). Since the upper limit is infinite, express the integral as a limit and analyze the behavior of the antiderivative as \(y \to \infty\) to determine convergence.

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Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Improper Integrals

Improper integrals involve integration over an infinite interval or where the integrand becomes unbounded. To evaluate them, the integral is expressed as a limit, ensuring convergence or divergence is properly determined.
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Integration by Parts

Integration by parts is a technique based on the product rule for differentiation. It transforms the integral of a product of functions into simpler integrals, often useful when one function simplifies upon differentiation and the other is easy to integrate.
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Logarithmic Functions in Integration

Integrals involving logarithmic functions often require special techniques like substitution or integration by parts. Understanding the properties of logarithms helps simplify the integrand and manage the behavior of the function, especially near limits.
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