Skip to main content
Ch. 8 - Techniques of Integration
Hass - Thomas' Calculus 15th Edition
Hass15th EditionThomas' CalculusISBN: 9780137616077Not the one you use?Change textbook
Chapter 8, Problem 8.PE.24

Evaluate the integrals in Exercises 9–28. It may be necessary to use a substitution first.
∫ [(2x³ + x² − 21x + 24) / (x² + 2x − 8)] dx

Verified step by step guidance
1
First, observe the integral \( \int \frac{2x^3 + x^2 - 21x + 24}{x^2 + 2x - 8} \, dx \). Since the degree of the numerator (3) is higher than the degree of the denominator (2), start by performing polynomial long division to simplify the integrand.
Divide \( 2x^3 + x^2 - 21x + 24 \) by \( x^2 + 2x - 8 \) to express the integrand as a polynomial plus a proper rational function (where the numerator degree is less than the denominator degree).
After the division, rewrite the integral as \( \int (\text{quotient} + \frac{\text{remainder}}{x^2 + 2x - 8}) \, dx \). Then, split the integral into two parts: one involving the polynomial quotient and the other involving the proper rational function.
Next, factor the denominator \( x^2 + 2x - 8 \) into \( (x + 4)(x - 2) \) to prepare for partial fraction decomposition of the proper rational function.
Set up the partial fraction decomposition for the proper rational function as \( \frac{A}{x + 4} + \frac{B}{x - 2} \), solve for constants \( A \) and \( B \), then integrate each term separately.

Verified video answer for a similar problem:

This video solution was recommended by our tutors as helpful for the problem above.
Video duration:
5m
Was this helpful?

Key Concepts

Here are the essential concepts you must grasp in order to answer the question correctly.

Polynomial Long Division

When the degree of the numerator is equal to or greater than the denominator in a rational function, polynomial long division is used to simplify the integrand. This process rewrites the integrand as a polynomial plus a proper fraction, making the integral easier to evaluate.
Recommended video:
07:00
Taylor Polynomials

Substitution Method

Substitution involves changing variables to simplify an integral, often by letting a part of the integrand equal a new variable. This technique is useful when the integral contains a composite function or when the derivative of a function appears elsewhere in the integrand.
Recommended video:
07:33
Euler's Method

Partial Fraction Decomposition

Partial fraction decomposition breaks a rational function into simpler fractions that are easier to integrate. After ensuring the fraction is proper, the denominator is factored, and the integrand is expressed as a sum of fractions with unknown coefficients to be determined.
Recommended video:
10:07
Partial Fraction Decomposition: Distinct Linear Factors