evaluate-the-limit-of-the-sequence-cn-tan-1left-frac12n12n-6-right-as-n-to-infty

Question

Evaluate the limit of the sequence cn=tan⁡−1(12n12n+6) c_n = \$$tan^{-1}$$\left( \frac{12n}{12n + 6} ight)  as n→∞ n 	o \infty .

Accepted Answer

π4\frac{\pi}{4}

Answer

π6\frac{\pi}{6}

Answer

π3\frac{\pi}{3}

Answer

π2\frac{\pi}{2}

Evaluate the limit of the sequence cn=tan−1(12n12n+6) c_n = \(\tan\)^{-1}\(\left\)( \(\frac{12n}{12n + 6}\) \(\right\)) as n→∞ n \(\to\) \(\infty\) .