Business Calculus
xk+1k+1arctan(x)−1k+1∫xk+11+x2dx+C\(\frac{x^{k+1}\)}{k+1}\(\arctan\)(x)-\(\frac{1}{k+1}\[\int\]\frac{x^{k+1}\)}{1 + x^2}\,dx+C
xk+1k+1arctan(x)−∫xk+11+x2dx+C\(\frac{x^{k+1}\)}{k+1}\(\arctan\)(x)-\(\int\]\frac{x^{k+1}\)}{1 + x^2}\,dx+C
xk+1arctan(x)−1k+1∫xk+11+x2dx+Cx^{k+1}\(\arctan\)(x)-\(\frac{1}{k+1}\[\int\]\frac{x^{k+1}\)}{1 + x^2}\,dx+C
xk+1arctan(x)−∫xk+11+x2dx+Cx^{k+1}\(\arctan\)(x)-\(\int\]\frac{x^{k+1}\)}{1 + x^2}\,dx+C