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8. Definite Integrals - Part 2 of 2!
8. Definite Integrals / Average Value of a Function / Problem 2
Problem 2

A tunnel is shaped in a form of a parabola with a base width of 800 ft800\(\text{ ft}\) and a maximum height of 600 ft600\(\text{ ft}\). Its cross-section can be modeled by y=600(1(x400)2) y = 600 \(\left\)( 1 - \(\left\)( \(\frac{x}{400}\) \(\right\))^2 \(\right\)) . What is the average height of the tunnel above the ground?