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Question

Let B(x)=∫bxf(t) dtB(x)=\int_{b}^{x}f\left(t\right)\,dt, and f(t)=4t+1f\left(t\right)=4t+1. Assuming that ff and f′$$f^{\prime}$$ are continuous functions for all real numbers, is B(x)B(x) a quadratic function?

Accepted Answer

Yes

Answer

No

Let B(x)=∫bxf(t)dtB(x)=\(\int\)_{b}^{x}f\(\left\)(t\(\right\))\,dt, and f(t)=4t+1f\(\left\)(t\(\right\))=4t+1. Assuming that ff and f′f^{\(\prime\)} are continuous functions for all real numbers, is B(x)B(x) a quadratic function?

Let $B (x) = \int_{b}^{x} f (t) d t$ , and $f (t) = 4 t + 1$ . Assuming that $f$ and $f^{'}$ are continuous functions for all real numbers, is $B (x)$ a quadratic function?