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16. Probability & Calculus
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Problem 3
16. Probability & Calculus
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16. Probability & Calculus / Continuous Probability Models / Problem 3
Problem 3
Using the CDF F(x)=1 - e^{-x^3} for x ≥ 0 derived from f(x)=3x^2 e^{-x^3}, compute P(1 ≤ X ≤ 3).
A
Approximately 0.632 (which corresponds to 1 - e^{-1}, mistakenly ignoring the e^{-27} term)
B
Approximately 0.000000000001879 because e^{-27} dominates the numerator and the other exponential cancels out
C
Exactly 1 - e^{-3^3} because probabilities over finite intervals with positive lower bound always simplify to one minus an exponential evaluated at the upper bound
D
Approximately 0.368 (exact form e^{-1} - e^{-27})
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