when-ht-0-give-both-times-and-identify-which-if-any-is-physically-meaningful-t-0

Question

A projectile's height (in meters) after tt seconds is modeled by h(t)=−5t2+20t+15h(t) = $$-5t^2 + 20t + 15. $$Use the quadratic formula to find when h(t)=0h(t) = 0. Identify which (if any) is physically meaningful.

Accepted Answer

t=2±7t = 2\pm\sqrt{7}Only t=2+7t = 2 + \sqrt{7} is physically meaningful

Answer

t=−2±7t = -2\pm\sqrt{7}Only t=−2+7t=-2+\sqrt{7} is physically meaningful

Answer

t=2±7t = 2\pm\sqrt{7}Both are physically meaningful

Answer

t=1±5t=1\pm\sqrt{5}Neither is physically meaningful

A projectile's height (in meters) after tt seconds is modeled by h(t)=−5t2+20t+15h(t) = -5t^2 + 20t + 15. Use the quadratic formula to find when h(t)=0h(t) = 0. Identify which (if any) is physically meaningful.

A projectile's height (in meters) after $t$ seconds is modeled by $h (t) = - 5 t^{2} + 20 t + 15$ . Use the quadratic formula to find when $h of t equals 0$ . Identify which (if any) is physically meaningful.