Beginning & Intermediate Algebra
a1=6a_1 = 6, r=2r = 2, an=6⋅2n−1a_{n}=6\(\cdot\)2^{n-1}
a1=6a_1=6, r=12r = 12, an=6⋅12n−1a_{n}=6\(\cdot\)12^{n-1}
a1=12a_1 = 12, r=2r=2, an=6⋅2n−1a_{n}=6\(\cdot\)2^{n-1}
a1=4a_1 = 4, r=3r = 3, an=4⋅3n−1a_{n}=4\(\cdot\)3^{n-1}