ve-x2-72x-3-0-by-completing-the-square-give-exact-roots-in-simplest-radical-form

Question

Solve x2+72x−3=$$0x^2$$+\frac72x-3=0 by completing the square. Give the exact roots in the simplest radical form.

Accepted Answer

x=−7±974x=\frac{-7\pm\sqrt{97}}{4}

Answer

x=−14±974x=\frac{-14\pm\sqrt{97}}{4}

Answer

x=−7±978x=\frac{-7\pm\sqrt{97}}{8}

Answer

x=−7±972x=\frac{-7\pm\sqrt{97}}{2}

Solve x2+72x−3=0x^2+\(\frac\)72x-3=0 by completing the square. Give the exact roots in the simplest radical form.